Understanding 01 intro to research methodology pdf gender studies feminism requires examining multiple perspectives and considerations. Question #b5f73 - Socratic. Then, we can just find the mass of 2.272 carbon atoms by multiplying 2.272 by the mass of 1 mole of carbon: 2.272 xx 12.01 = "27.29g" Since there was 1 significant figure in the question, our answer is "30g". Another way to solve this problem is by using the mass percent! Explanation: #M_ (CO_2) = "220 mg"# #MW_ (CO_2) = "44.01 g/mol"# #"O"_2 " molecules = ?"#
675N Here,the kinetic energy of the hammer head got totally converted to the work done in moving the nail through a distance of 10 mm or 0.01 m So, kinetic energy of the hammer during the strike was 1/2 m v^2=1/2×1.5×3^2=6.75J Now,if an average force of F had acted on the nail to move it by 0.01 m,then work done by the force will be (F×0.01)J(using W=F*s) So,we can equate both 6.75=F×0.01 ... 1545 subjects were given ginko & 1524 placebo. In ginko group, 246 developed dementian & in the placebo it was 277 with dementia.
Significance level=0.01 to test claim (ginko is effective in dementia) Can you test claim and construct confidence interval? 65.0 "g N"_2 Any time you want to convert between moles and grams of a substance, you must know that substance's molar mass, which is the mass of one mole of that substance. Similarly, (One mole is equal to Avogadro's number (6.022xx10^23) of individual particles/molecules of that substance.) To find the molar mass of a nitrogen molecule, we'll first realize its chemical formula, which is "N"_2. Can anyone please answer this chemistry difficulty?
E^@ = 0 Q = ( ["Zn"^"2+"]_text (prod))/ ( ["Zn"^"2+"]_text (react)) = (0.01 color (red) (cancel (color (black) ("mol/L"))))/ (1 color (red) (cancel (color (black) ("mol/L")))) = 0.01 E = E^@ - (RT)/ (zF)lnQ = - ("8.314 V"·color (red) (cancel (color (black) ("C·K"^"-1""mol"^"-1"))) × 298.15 color (red) (cancel (color (black) ("K"))))/ ("2 × ... 0.56 1 molar solution ="Number of moles of solute"/"Volume of solution" for Sugar C_ (12)H_ (22)O_ (11) molar mass=342gm according to equation and information provided 1= (3.42/342)/x where x is the volume of solution in l :. the volume of solution is 0.01 l which is 10 ml :.10 gm of water . moles of solute=3.42/342=0.01 moles of solution =10/18=0.55 :.
This perspective suggests that, the mole fraction of the solution is 0. 4 ⋅ 12.01 = 48.04 g We now know that one mole of carbon contains 48.04 grams of carbon. Next, we determine how many grams of carbon are in one mole of CO. With this information, we can determine how many moles of CO can be formed with the given mass of C.
How do you solve X * 0.01 = 637? Multiply each side by color (red) (100) X * color (red) (100) * 0.01 = color (red) (100) * 637 X * 1 = 63700 X = 63700 The degree of dissociation sf (alpha=0.0158) sf (K_b=2.51xx10^ (-6)color (white) (x)"mol/l") Triethyamine is a weak base and ionises: sf ( (CH_3)_3N+H ...
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